Electrical Power
Electrical Energy and Electrical Power
Work:
In physics, work is said to be done when a force is applied to an object,
causing it to move in the direction of the force. Mathematically, work (W) is
defined as the product of the force (F) applied to an object and the
displacement (d) of the object in the direction of the force.
W
= F x d
Recall, Potential
Difference or Voltage is mathematically written as follows:
Voltage
(V) = Work done (W) / Charge (Q)
Or W = V
x Q ------------- (i)
Energy: Energy is the ability to do work.
Electrical
energy is the energy related with the movement of charged particles i.e. electrons
through a conductor in an electric circuit. It is the ability of an electric
current to do work.
From equation (i), we get -
Electrical
Energy (E) = V × Q ------------- (ii)
Power:
Power is the rate at which work is done or the rate at which energy is
transferred or converted. In electrical systems, power is the rate at which
electrical energy is transferred or used.
Mathematically,
Power =
Work done or Energy transferred or Converted / Time
P = E / t
------------- (iii)
Using
(ii) in (iii), we have
P = V x Q
/ t
P = V x I
{from definition of Current (I) =Q / t} ———- (iv)
The SI
unit of electric power is watt (W). It is the power consumed by a device that
carries 1 A of current when operated at a potential difference of 1 V. Thus,
1 W = 1
volt × 1 ampere = 1 V A
The unit
watt is small; therefore, Kilowatt is used.
Electrical
Power = Voltage x Current, the unit is watts (W)
We know
Energy =
Power x Time where unit of Energy is Joule, unit of Power is Watt
Ex. If I
purchase a bulb of 60 Watt, it means it consumes 60 Joules of Electrical Energy
per second.
Energy
supplied to the circuit by the source in time t,
E = P x t
= V x I x
t {from (iv)}
The unit
for electric energy is watt hour (W h). The commercial unit of Electric energy
is kilowatt hour (kW h),
1 kW h =
1000 watt × 3600 second
= 3.6 x 10⁶ Watt-Second
= 3.6 x 10⁶ joule (J)
Solved Numerical:
1. An electric
bulb is connected to a 220 V generator. The current is 0.50 A. What is
the
power of the bulb?
Given: V = 220 Volt and I = 0.50 A
We know,
P = V x I = 220 x 0.5 = 110 J/s or Watth 2. Two lamps, one rated 100 W at 220 V, and the other 60 W
at 220 V, are connected in parallel to electric mains supply. What current is
drawn from the line if the supply voltage is 220 V? Also find the total resistance. Given: P1 = 100 W, P2 = 60 W, V = 220 V
a)
We
know, P = V x I
I
= P/V
I1
= P1/V
=
100/220 A
Resistance
of Lamp 1
V
= I x R
R1
= V/I1
=
220/100/220 ohms
=
220 x 220 /100
Similarly,
b)
I2
= P2/V
=
60/220 A
R2
= V/I2
=
220/60/220
=
220 x 220/60
= 2420/3 ohms
To find
equivalent Resistance, Both Lamps are connected in parallel
1/R
= 1/R1 + 1/R2
=
1 / 484 + 3 / 2420
=
2420 / 8 ohms
To
find Current drawn through mains
I
= V / R
=
220 / (2420 / 8)
=
220 x 8 /2420 A
= 0.73 A
No comments: